5p^2=231

Solution for 5p^2=231 equation:

5p^2=231

We move all terms to the left:

5p^2-(231)=0

a = 5; b = 0; c = -231;
Δ = b2-4ac
Δ = 02-4·5·(-231)
Δ = 4620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4620}=\sqrt{4*1155}=\sqrt{4}*\sqrt{1155}=2\sqrt{1155}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1155}}{2*5}=\frac{0-2\sqrt{1155}}{10}
=-\frac{2\sqrt{1155}}{10}
=-\frac{\sqrt{1155}}{5}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1155}}{2*5}=\frac{0+2\sqrt{1155}}{10}
=\frac{2\sqrt{1155}}{10}
=\frac{\sqrt{1155}}{5}
$